ce pressure is constant, use Charles's law form: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] Step 4: Solve for \( V_2 \): \[ V_2 = V_1 \times \frac{T_2}{T_1} = 12.0 \times \frac{373}{293} \] \[ V_2 \approx 12.0 \times 1.272 \
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V_1 = 10.0\,L \), \( P_1 = 1.00\,atm \), \( T_1 = T_2 = 300\,K \) Final: \( P_2 = 2.00\,atm \), \( V_2 = ? \) Use the combined gas law: \[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \] Since \( T_1 = T_2 \), the t
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